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13x+x^2=121
We move all terms to the left:
13x+x^2-(121)=0
a = 1; b = 13; c = -121;
Δ = b2-4ac
Δ = 132-4·1·(-121)
Δ = 653
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{653}}{2*1}=\frac{-13-\sqrt{653}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{653}}{2*1}=\frac{-13+\sqrt{653}}{2} $
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